270 g Al impur ......................... 100%
m.pur ...................................... 90%
= 243 g Al pur
243g md
2Al + 3H2SO4 --> Al2(SO4)3 + 3H2
2x27 3x98
=> md = 243x3x98/2x27
= 1323 g H2SO4
stim ca c% = mdx100/ms
=> ms = mdx100/c%
= 1323x100/20 = 6615 g sol. H2SO4
ro = p = ms/Vs
=> Vs = ms/p = 6615/1,104
= 5991,85 mL sol. H2SO4
