Alcan CnH2n+2
=> 2n+2/n = 2,4 => n = 2/0,4 = 5
=> alcanul A = C5H12
d)
a = C3H6
B = izopentan CH3CHCH2CH3
CH3
b = CH4
CH3
C = neopentan, CH3CCH3
CH3
CH3
c = clorura de neopentil, CH3CCH2Cl
CH3
e)
3 kmoli m kg
C5H12 + Cl2 --> C5H11Cl + HCl
1 106,5
=> m = 3x106,5/1 = 319,5 kg compus c obtinut teoretic la 100% ... dar cat s-ar fi obtinut la 80%
100% .......................... 319,5 kg c (Ct)
80% ............................ Cp = 255,6 kg c
f)
C, B, A
----------> creste p.f.oC
