Răspuns:
m=400g=0.4kg
Pe axa OY: N+F_{y}=GN+Fy=G => N= G-F_{y}N=G−Fy
F_{y} = F*sin( \alpha )=6*sin(30)=6* \frac{1}{2}=3NFy=F∗sin(α)=6∗sin(30)=6∗21=3N
G = m*g = 0.4*10=4NG=m∗g=0.4∗10=4N
Deci N=4-3=1NN=4−3=1N
Rezulta ca raportul \frac{G}{N} = \frac{4}{1} = 4NG=14=4
