Răspuns :
a) x-1=3
x=4
x-1=-3
x=-2
b)x+4=-1
x=-5
x+4=1
x=-3
c) 1-x=4
-x=3
x=-3
1-x=-4
-x=-5
x=5
d) x-1≤3
x≤4
x∈(-∞,4]
x-1≤-3
x≤-2
x∈(-∞,-2]
e) x+2≥2
x≥0
x∈(+∞,0]
a) Deoarece | 3|=3 si | -3 | =3 avem 2 posibilitati
x - 1 = 3 ⇒ x = 4
x - 1 = - 3 ⇒ x = - 3+1= - 2
b) nu are solutie pentru ca modulul unui numar este > 0
c) 1 - x = 4 ⇒ - x = 4 - 1=3⇒x= - 3
1 - x = - 4⇒ - x = - 4 - 1= - 5⇒x = 5
d) x - 1 <= 3⇒ x<= 4⇒x∈{0,1,2,3,4}
-x + 1 <=3⇒ - x<=2⇒ - x∈{0,1,2}⇒x∈{0, - 1, - 2}
e)x + 2>= 2⇒x>=0
- x - 2>=2⇒ - x>= 4⇒ - x∈{4,5,6....,}⇒x∈{-4,-5,-6,....}
f) x+5<=2⇒x<= -3(2-5)⇒x∈{-3,-4,-5,-6,..}
-x-5<=2⇒-x<=7⇒x∈{0,-1,-2,-3,-4,-5,-6,-7}
g)x-3≥ -3⇒x≥0
-x+3≥-3⇒ - x ≥ - 6⇒x∈{6,5,4,3,2,1,0}
x - 1 = 3 ⇒ x = 4
x - 1 = - 3 ⇒ x = - 3+1= - 2
b) nu are solutie pentru ca modulul unui numar este > 0
c) 1 - x = 4 ⇒ - x = 4 - 1=3⇒x= - 3
1 - x = - 4⇒ - x = - 4 - 1= - 5⇒x = 5
d) x - 1 <= 3⇒ x<= 4⇒x∈{0,1,2,3,4}
-x + 1 <=3⇒ - x<=2⇒ - x∈{0,1,2}⇒x∈{0, - 1, - 2}
e)x + 2>= 2⇒x>=0
- x - 2>=2⇒ - x>= 4⇒ - x∈{4,5,6....,}⇒x∈{-4,-5,-6,....}
f) x+5<=2⇒x<= -3(2-5)⇒x∈{-3,-4,-5,-6,..}
-x-5<=2⇒-x<=7⇒x∈{0,-1,-2,-3,-4,-5,-6,-7}
g)x-3≥ -3⇒x≥0
-x+3≥-3⇒ - x ≥ - 6⇒x∈{6,5,4,3,2,1,0}