Răspuns:
Explicație pas cu pas:
b) |-i|=1
teta=3π/2
-i=cos3π/2+isin3π/2
c) |3|=3
teta=0
3=3(cos0+isin0)
d) | 1+i√3|=2
costeta=1/2...sinteta=√3/3 teta=π/6
1+i√3=2(cosπ/6+isinπ/6)
e)|1-i√3|=2
cos teta=1/2....sin teta=-√3/2...teta=5π/3
1-i√3=2(cos5π/3+isin5π/3)
f) |-1-i√3|=2
costeta=-1/2....sinteta=-√3/2....teta=4π/3
-1-i√3=2(cos 4π/3+isin4π/3)
