Răspuns:
1.
MCO2=12+2×16=44g/mol
n=440/44=10moli
MH2O =2×1+16=18g/mol
n=360/18=20moli
MNaOH =23+16+1=40g/mol
n=120/40=3moli
MH2SO4 =2×1+32+4×16=98g/mol
n=392/98=4 moli
2.
MMgO=24+16=40g/mol
MMMg24g/mol
MO2=2×16=32g/mol
2×24g 32g 2×40g
2Mg + O2=> 2MgO
240g xgO ygMg
x=240×32/2×24=160gO2 consumat
y=240×40/2×24=200gMgO obținut