Răspuns:
A,Fe=56g/mol
V,M=22,4L/mol
miu,FeCl3=162,5 g/mol
-calculez masa si moli de fier pur, stiind p=80%
p=m,px100/m,i----> m,p= 80x700/100g=560g fier pur
niu=m/A=560/56mol=10moLFe
-deduc moli Cl2 si FeCL3, din ecuatia chimica
2mol......3mol........2mol
2Fe + 3CL2----> 2FeCl3
10mol.......x................y
x= 15mol Cl2
y=10mol FeCl3
V.Cl2=niuxVm= 15x22,4 l=336 l
m,FeCl3=niuxmiu=10x162,5g=1625g
Explicație:
