Explicație pas cu pas:
[tex] 2 \times {2}^{2} \times ... {2}^{2002} = {2}^{1 + 2 + ... + 2002} = {2}^{ \frac{2002 \times 2003}{2} } = {2}^{1001 \times 2003 } = {2}^{2005003} [/tex]
[tex]( {8}^{77} )^{8671} = {8}^{667667} = ({ {2}^{3} })^{667667} = {2}^{2003001} [/tex]
[tex] {2}^{2005003 } > {2}^{2003001} [/tex]
