Răspuns:
Explicație pas cu pas:
a) in ΔCMD ∡CMD=60° pt ca are complement ∡MCA=30°
tg60°=DC/CM=√3
CM=8√3/2=4√3 cm ⇒CD=CM√3=4√3×√3=4×3=12 cm
b)Aamcd=(AM+CD)×CM/2=(4+12)×4√3/2=16×2√3=32√3 cm²