Răspuns:
[tex]a)[ ({3}^{2} ) {}^{5} \div {3}^{7} - {3}^{0} - {3}^{2} ] \times 4\div 34 + {2}^{2} = \\ ( {3}^{10} \div {3}^{7} - 1 - 9) \times 4 \div 34 + 4 = \\ ( {3}^{3} - 1 - 9) \times 4 \div 34 + 4 = \\ (27 - 1 - 9) \times 4 \div 34 + 4 = \\ (26 - 9) \times 4 \div 34 + 4 = \\ 17 \times 4 \div 34 + 4 = \\ 68 \div 34 + 4 = \\ 2 + 4 = 6 \\ \\ c)( {25}^{4} ) {}^{3} \div ( {4}^{2} + {3}^{2} ) {}^{11} - ( {0}^{2010} + {1}^{2012} + {2013}^{0} ) {}^{2} = \\ {25}^{12} \div (16 + 9) {}^{11} - (0 + 1 + 1) {}^{2} = \\ {25}^{12} \div {25}^{11} - {2}^{2} = \\ 25 - 4 = 21 \\ \\ d)[ {3}^{3} \times 3 + {2}^{45} \div {2}^{42} + ( {3}^{5} ) {}^{6} \div {3}^{29} + {9}^{0} ] \div 31 = \\ ( {3}^{4} + {2}^{3} + {3}^{30} \div {3}^{29} + 1) \div 31 = \\ (81 + 8 + 3 + 1) \div 31 = \\ (89 + 3 + 1) \div 31 = \\ (92 + 1) \div 31 = \\ 93 \div 31 = 3[/tex]
nu știu cum se termină b si e,de aceea nu le-am facut.
sper că te-am ajutat!
