Răspuns:
[tex]\int {\frac{x+1}{x-2} } \, dx= \int {\frac{x-2+2+1}{x-2} } \, dx=\int {(\frac{x-2}{x-2}+\frac{3}{x-2})} \, dx=\int {(1+\frac{3}{x-2}) } \, dx=\int {1} \, dx+3*\int{\frac{1}{x-2}} \, dx=x+3*\int {\frac{1}{x-2} } \, d(x-2) =x+3ln|x-2|+C.[/tex]
Explicație pas cu pas:
x∈R\{2}
