Smartdarnupreaask
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URGENT!!!
|x+1|(|x+1|-5) mai mic sau egal cu zero
Aflați x​

Răspuns :

Raytheweebask

Răspuns:

|x-1|(|2x-1|-5)<0, x∈ Z*

|a| ≥ 0, ∀ a ∈ IR

↓

|x-1| ≥ 0

|x-1|(|2x-1|-5)<0

⇒ |2x-1|-5<0

⇒ |2x-1| < 5 ⇔ -5 < 2x-1 < 5 | + 1

-4 < 2x < 6 | :2

-2 < x < 3

x ∈ Z* ⇒ S = {-1,1,2}

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