Răspuns:
[tex]1)(4 + {2}^{232} \div {2}^{230} ) \div {2}^{2} = \\ (4 + {2}^{2} ) \div {2}^{2} = \\ (4 + 4) \div {2}^{2} = \\ 8 \div 4 = 2 \\ \\ 2)(225 \div {5}^{2} + {5}^{0} ) {}^{3} \div {10}^{2} = \\ (225 \div 25 + 1) {}^{3} \div {10}^{2} = \\ (9 + 1) {}^{3} \div {10}^{2} = \\ {10}^{3} \div {10}^{2} = 10 \\ \\ 3) ({7}^{14} \div {7}^{12} - {7}^{0} ) \div {2}^{4} = \\ ( {7}^{2} - 1) \div {2}^{4} = \\ (49 - 1) \div {2}^{4} = \\ 48 \div 16 = 3 \\ \\ 4) {5}^{3} \div [ {2}^{5} - (7 \times {2}^{7} \div 14 - {7}^{0} ) \div {3}^{2}] = \\ {5}^{3} \div [32 - (7 \times {2}^{7} \div 2 \div 7 - 1) \div {3}^{2} ] = \\ {5}^{3} \div[32 - (1 \times {2}^{6} - 1) \div {3}^{2} ] = \\ {5}^{3} \div [32 - (64 - 1) \div {3}^{2} ] = \\ {5}^{3} \div (32 - 63 \div 9) = \\ {5}^{3} \div (32 - 7) = \\ {5}^{3} \div 25 = \\ {5}^{3} \div {5}^{2} = 5[/tex]
sper că te-am ajutat!
