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122+12x{183:[(2x3^2x5^3)^4:(2^4x3^7x5^12)+(2^8)^9:2^72-127x5^0]-9x(54-2^4x3)}
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Răspuns :

Dianageorgiana794ask

Răspuns:

122+12·{183:[(2·3²·5³)⁴:(2⁴·3⁷·5¹²)+(2⁸)⁹:2⁷²-1²⁷·5⁰] -9·(54-2⁴·3)}=

122+12·{183:[(2⁴·3⁸·5¹²):(2⁴·3⁷·5¹²)+2⁷²:2⁷²-1·1] -9·(54-16·3)}=

122+12·{183:2⁴⁻⁴·3⁸⁻⁷·5¹²⁻¹²+2⁷²⁻⁷²-1] -9·(54-48)}=

122+12·{[183:2⁰·3¹·5⁰+2⁰-1]-9·6}=

122+12·[(183:1·3·1+1-1)-54]

122+12·[183:3-54]=

122+12·(61-54)=

122+12·7=

122+84=

206

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