Răspuns :
[tex]( \sqrt{3} + \sqrt{5} ) \sqrt{3} = \sqrt{3} \sqrt{3} + \sqrt{5} \sqrt{3} = 3 + \sqrt{15} [/tex]
[tex](3 - \sqrt{2}) \times ( - \sqrt{2} ) = - 3 \sqrt{2} - \sqrt{2} \times ( - \sqrt{2}) = - 3 \sqrt{2} + 2[/tex]
[tex]( - 2 \sqrt{3} ) \times ( \sqrt{3} - \sqrt{6} ) = - 2 \sqrt{3} \times ( \sqrt{3} - \sqrt{6} ) = - 6 + 2 \sqrt{18} = - 6 + 6 \sqrt{2} [/tex]
[tex] \sqrt{2} ( \sqrt{2} - \sqrt{6} + \sqrt{10} ) = 2 - \sqrt{12} + \sqrt{20} = 2 - 2 \sqrt{3} + 2 \sqrt{5} [/tex]
[tex]( \sqrt{3} + \sqrt{5} ) \times \sqrt{3} = \sqrt{3} \times \sqrt{3} + \sqrt{3} \times \sqrt{5} = \sqrt{9} + \sqrt{15} = 3 + \sqrt{15} [/tex]
[tex](3 - \sqrt{2} ) \times ( - \sqrt{2} ) = - \sqrt{2} \times 3 - ( - \sqrt{2} ) \times \sqrt{2} = - \sqrt{2} \times 3 + \sqrt{4} = = - 3\sqrt{2} + 2[/tex]
[tex]
( - 2 \sqrt{3} ) \times ( \sqrt{3} - \sqrt{6} ) = - 2 \sqrt{3} \times \sqrt{3} - ( - 2\sqrt{3} ) \times \sqrt{6} = - 2 \sqrt{9} + 2 \sqrt{18} = \sqrt{27} = - 6 + 2 \times 3 \sqrt{2} = - 6 + 6 \sqrt{2}
[/tex]
[tex] \sqrt{2} ( \sqrt{2} - \sqrt{6} + \sqrt{10} ) = \sqrt{2} \times \sqrt{2} - \sqrt{2} \times \sqrt{6} + \sqrt{2} \times \sqrt{10} = \sqrt{4} - \sqrt{12} + \sqrt{20} = 2 - 2 \sqrt{3} + 2 \sqrt{5} [/tex]