Răspuns:
A. 2^2015(2^2-2^1-1):2^2:2^2008+1*1=
2^2015*1:2^2:2^2008+1=2^5=32
B(1+27^1350:9^2000):2^100=
(1+3^4050:3^4000):2^100=
1+3^50:2^100
C2^6:2^6+3^4:(64-36-1)=
2^0+3^4:27=1+3^4:3^3=1+3^1=1+3=4
