Răspuns:
b)
(3^57:9^25
[tex]b)( {3}^{57} \div {9}^{25} \times {3}^{10} ) \div {3}^{15} = \\ ( {3}^{57} \div ( {3}^{2} ) ^{25} \times {3}^{10} ) \div { 3}^{15} = \\ ( {3}^{57} \div {3}^{50} \times {3}^{10} ) \div {3}^{15} = \\ ( {3}^{7} \times {3}^{10} ) \div {3}^{15} = \\ {3}^{17} \div {3}^{15} = {3}^{2}= {9} [/tex]
sper că te-am ajutat!!!
