Răspuns:
u=i+j
v= -i+2j
W=5i-j
w=au+bv unde a, b∈R*
5i-j=a(i+j)+b(-i+2j)
5i-j=ai+aj-bi+2bj
5i-j=(ai-bi)+(aj+2bj)
5i-j=(a-b)i+(a+2b)j
Sistem
{a-b=5
{a+2b=-1
Scadem prima ecuatie din a 2-a
a+2b-(a-b)= -1-5
a+2b-a+b=-6
3b= -6
b= -2
Inlocuiesti b in prima ecuatie
a-(-2)=5
a+2=5
a=5-2=3
w=3i-2j
b) conditia de coliniaritate
2u+v=2(i+j)-i+2j=2i+2j-i+2j=
i+4j
conditia de coliniaritate
1/(m-3)=4/(m+3)
m+3=4(m-3)
m+3=4m-12
3+12=4m-m
15=3m
m=15:3=5
Explicație pas cu pas: