Răspuns:
2^11 - 1
Explicație pas cu pas:
S = 2^0+2^1+2^2+...+2^10 | x2
2S = 2^1+2^2+...+2^10+2^11
2S = (2^0+2^1+2^2+...+2^10)-2^0+2^11
2S = S - 1 + 2^11
2S - S = 2^11 - 1
S = 2^11 - 1
[tex]\it \dfrac{..}{..}\ \ S_n=b_1\cdot\dfrac{q^n-1}{q-1}\\ \\ \\ Din\ enun\c{\it t} \Rightarrow\ b_1=2^0=1,\ \ \ q=2\\ \\ \\ S_{11}=\dfrac{2^{11}-1}{2-1}=2^{11}-1[/tex]
