Răspuns:
[tex]5-2\sqrt{6}[/tex]; [tex]\frac{6\sqrt{3}-\sqrt{15} }{18}[/tex]
Explicație pas cu pas:
[tex]\frac{\sqrt{3}-\sqrt{2} }{\sqrt{3}+\sqrt{2} } =\frac{(\sqrt{3}-\sqrt{2} )(\sqrt{3}-\sqrt{2} )}{(\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2} )} =\frac{(\sqrt{3}-\sqrt{2} )^{2} }{3-2}=5-2\sqrt{6}[/tex]
[tex]\frac{6-\sqrt{5} }{3\sqrt{12} } =\frac{6-\sqrt{5} }{3\sqrt{2^{2}*3 } } =\frac{6-\sqrt{5} }{6\sqrt{3} }=\frac{(6-\sqrt{5})\sqrt{3} }{6\sqrt{3}\sqrt{3} } =\frac{6\sqrt{3}-\sqrt{15} }{18}[/tex]