Răspuns:
a. (3^10:3^7-3^0-3^2)•4:34+2^2
=(3^3-1-9)•4:34+4=
=17•4:34+4=
=2+4=6.
b. (123+2^9+2^40):(123+2^9+2^10)
=1 deoarece imparti aceeasi suma la aceeasi suma.
c.25^12:(16+9)^11-(1+1)^2
=25^12:25^11-4=
=25-4=21
d.(27•3+2^3+3^30:3^29+1):31
=(81+8+3+1):31=
=93:31=3
e.(256+81+15625+1296):(256+81+15625+1296)=1
