Răspuns:
a) [tex]\frac{2*3+1}{3}*0,3+\frac{3*2+1}{2}*0,2-\frac{1}{6}*0,6=7*0,1+7*0,1-0,1=0,1(7+7-1)=0,1*13=1,3[/tex]
b) [tex]\frac{1*4+1}{4} *0,15-\frac{3}{9}*0,9+\frac{27-2}{90}*32:8= \frac{5}{4} *0,15-3*0,1+\frac{25}{90}*4=\frac{0,75}{4}-0,3+\frac{5}{18}*4= \frac{75}{400}-\frac{3}{10}+\frac{10}{9}=\frac{3(45}{16}-\frac{3(72}{10}+\frac{10(80}{9}= \frac{135-216+800}{720}=\frac{719}{720}[/tex]
c)
Explicație pas cu pas: