Răspuns :
[tex]\it \left.\begin{aligned}\it \Big(\dfrac{5}{2}\Big)^2= \Big(\dfrac{2}{5}\Big)^{-2}\\ \\ \\ \it \Big(\dfrac{\ 6^{(3}}{15}\Big)^3=\Big(\dfrac{2}{5}\Big)^3 \end{aligned}\right\} \Rightarrow \Big(\dfrac{5}{2}\Big)^2\cdot\Big(\dfrac{6}{15}\Big)^3= \Big(\dfrac{2}{5}\Big)^{-2}\cdot\Big(\dfrac{2}{5}\Big)^3=\Big(\dfrac{2}{5}\Big)^{-2+3}=\dfrac{2}{5}[/tex]