Răspuns :
[tex]\it a)\ =24:12+\sqrt{3^{10}}=2+\sqrt{(3^5)^2}=2+3^5=2+243=245\\ \\ b)\ = \sqrt7\cdot6\cdot3\cdot25+7\cdot\sqrt3\cdot5\sqrt3\cdot11=\sqrt7\cdot6\cdot3\cdot25+7\cdot3\cdot5\cdot11=[/tex]
[tex]\it a)\ =24:12+\sqrt{3^{10}}=2+\sqrt{(3^5)^2}=2+3^5=2+243=245\\ \\ b)\ = \sqrt7\cdot6\cdot3\cdot25+7\cdot\sqrt3\cdot5\sqrt3\cdot11=\sqrt7\cdot6\cdot3\cdot25+7\cdot3\cdot5\cdot11=[/tex]