Răspuns:
b) (1/6;1/5]....(-17/6; -14/5}
c) 3n+1
Explicație pas cu pas:
x∈[5.6) deci 1/x∈(1/6;1/5]
[1/x-3]∈=(-1/6-3; 1/5-3]=(-17/6; -14/5}
c) asta e si mai greu...
dar..
[ n+1+n+2√(n²+2n)]=2n+1+[√(n²+2n)]
dar n=\n|=√n²<√(n²+2n)<√(n²+2n+1)=|n+1|=n+1
deci 2n+1+[√(n²+2n)]=2n+1+n=3n+1`
