Răspuns:
Explicație pas cu pas:
a) 5x(x+2)+10(x+2) =5(x+2)(x+2)=5(x+2)²
b) (x+y)²-z²=(x+y+z)(x+y-z)
c) x³-4x²+4x=x(x²-4x+4)=x[(x²-4) -(4x-4-4)]=x[(x-2)(x+2)-(4x-8)]=x[(x-2)(x+2)-4(x-2)]=x[(x-2)(x+2-4)]=x(x-2)(x-2)=x(x-2)²
d) (x³+t³)+(x²t+xt²) = (x+t)(x²-xt+t²)+xt(x+t)=(x+t)(x²-xt+t²+xt)=(x+t)(x²+t²)
