Răspuns:
Amplitudinea 5
faza initiala π/2
ω=3π/2
Intersectia cu Ot
5cos(3πt/2+π/2)=0
cos(3πt/2+π/2)=0=>
(3πt/2+π/2)=π/2=>
3πt/2+π/2=0=.>
=>x=2kπ+π/2 pt ca f cos este periodica k∈N
Intersctia cu Oy
5cos(3π/2t+π/2)=0=.>
cos(3πt/2+π/2)=0=>
3π/2+π/2=π/2=>
t=0
Explicație:
