Răspuns:
a. a²+ 4a+4+b²-6b+9 = (a+2)²(b-3)²=0
a=-2; b=3
Explicație pas cu pas:
b. 4a²-12a+9+b²+b+1 = (2a-3)²(b+1)²
a = 3/2; b = -1
d. 4a² +9b²+ 12ab +b²+2b+1= (2a+3b)²(b+1)² = 0
a= -3b/2; b=-1
c. a²-2a+1+4a²+4ab+b² = (a-1)²(2a+b)² = 0
a= 1; b= -2a