Răspuns:
1 intreg si 5/6=(1·6+5)/6=11/6
11/6+[(²⁾1-1/2)·(³⁾2-2/3)]² =
11/6+[(2/2-1/2)·(6/3-2/3)]² =
11/6+(1/2·4/3)²= se simplifica 2 si 4
11/6+(2/3)²=
³⁾11/6+²⁾4/9=33/18+8/18=41/18
