Explicație:
[tex]niu = \frac{n}{na} \\ niu = \frac{18.06 \times 10^{23} }{6.023 \times 10 ^{23} } \\ niu = 3 \\ dar \: \\ niu = \frac{m}{m molar} \\ mmoalr = 32 \\ m = niu \times mmolar = 32 \times 3 = 96g \\ \\ [/tex]
densitatea=
[tex] \frac{m}{vam} = \\ \frac{96}{8.31} = 1.15[/tex]
[tex]pv = niu \times r \times t \\ \\ p = \frac{niu \times r \times t}{v} = \\ \\ p = \frac{3 \times 8.31 \times 320}{ 83.1 } = 0.96 \times 10^{5} pa[/tex]
