Rbianca68ask
a fost răspuns

6(x-1)²-(2x+1)(3x-2)≥8+10x

Răspuns :

Andrei115ask
6(X² - 2X + 1) - (6X² - 4X + 3X - 2) ≥ 8 + 10X
6X² - 12X + 6 - 6X² + 4X - 3X + 2 ≥ 8 + 10X
-11X + 8 ≥ 8 + 10X
-11X - 10 X ≥ 8 - 8
-21X ≥ 0
21X ≤ 0
X ≤ 9
Deeamadalinaask
6(x²-2x+1)-6x²+4x-3x+2≥8-10x
6x²-12x+6-6x²+x+2≥8-10x
-12x+x+10x≥8-6-2
-x≥0/(-1)
x≤0