JESSICASPOIALAask
a fost răspuns

Efectuat-i calculele:(3+3sus2)2sus2-2017sus0+1sus2016

Răspuns :

Salutare!!!

[tex] \bf(3 + {3}^{2}) \cdot {2}^{2} - {2017}^{0} + {1}^{2016} = [/tex]

[tex]\bf(3 + 9) \cdot 4 - 1 + 1 = [/tex]

[tex]\bf12 \cdot 4 - 1 + 1 = [/tex]

[tex]\bf 48 - 1 + 1 = [/tex]

[tex] \boxed{\bf 48}[/tex]

a⁰ = 1

1ⁿ = 1