sa se descompuna in factori:
[tex](x + 2) {}^{2} - (x - 1) { }^{2} [/tex]


Răspuns :

(x+2)²-(x-1)²=

=(x+2+x-1)(x+2-x+1)=3(2x+1)

[tex]\left(x+2\right)^2-\left(x-1\right)^2[/tex]

[tex]= \left(x+2\right)^2:\quad x^2+4x+4[/tex]

[tex]=x^2+4x+4-\left(x-1\right)^2[/tex]

[tex]= \left(x-1\right)^2:\quad x^2-2x+1[/tex]

[tex]= -\left(x^2-2x+1\right)[/tex]

[tex]= \quad -x^2+2x-1[/tex]

[tex]=x^2+4x+4-x^2+2x-1[/tex]

[tex]=x^2-x^2+4x+2x+4-1[/tex]

[tex]=4x+2x+4-1[/tex]

[tex]=6x+4-1\\[/tex]

[tex]=6x+3[/tex]

Sper că te-am ajutat!

Succes!