Notam cu:
a - primul numar
b - al doilea numar
c - al treilea numar
[tex]\bf a+b+c = 2650[/tex] (relatia 1)
[tex]\bf a = b +550\Rightarrow b = a-550[/tex] (relatia 2)
[tex]\bf b = c:2\Rightarrow c = 2b[/tex] (relatia 3)
inlocuim pe b din relatia 2 in relatia 3 si vom avea
[tex]\bf c = 2 (a-550)\Rightarrow c = 2a -1100[/tex]
[tex]\bf a + a -550 +2a -1100 = 2650[/tex]
[tex]\bf 4a -1650 = 2650[/tex]
[tex]\bf 4a = 2650 +1650[/tex]
[tex]\bf 4a = 4300\:\:\:|:4[/tex]
[tex]\boxed{\bf a = 1075}[/tex]
[tex]\bf b = 1075-550[/tex]
[tex]\boxed{\bf b = 525}[/tex]
[tex]\bf c = 2\cdot 525[/tex]
[tex]\boxed{\bf c = 1050}[/tex]
Verificare:
1075 + 525 + 1050 = 2650 (adevarat)
Raspuns:
