[tex]\bf \dfrac{7}{3} +\dfrac{3}{4}-\dfrac{1}{6}=[/tex]
[tex]\bf \dfrac{7\cdot4}{12} +\dfrac{3\cdot3}{12}-\dfrac{1\cdot2}{12}=[/tex]
[tex]\bf \dfrac{28+9-2}{12} =[/tex]
[tex]\boxed{\bf \dfrac{35}{12}}[/tex] sau [tex]\boxed{\bf 2\dfrac{11}{12}}[/tex]
Raspuns:
7/3+3/4-1/6=28/12+9/12-1/6=37/12-2/12=35/12
