Poate cineva sa ma ajute va rog

[tex]\it c)\: x(x+1)=x^{2} +2x+1\\\\x^{2}+x=x^{2} +2x+1\\\\x=2x+1\\\\2x-x=-1 \Rightarrow \boxed{\it x=-1}\\\\\\e)\:5(1-2x)+1=4(x+3)+8\\\\5-10x+1=4x+12+8\\\\6-10x=4x+20\\\\6-20=4x+10x\\\\-14=14x\\\\x=\dfrac{-14}{14}\Rightarrow\boxed{\it x=-1}[/tex]