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[4la puterea7×(-4)la12÷(-4)la15]la12÷(-4)la44

Răspuns :

[tex]\left[4^7\cdot(-4)^{12}:(-4)^{15}\right]^{12}:(-4)^{44}=(-4^7\cdot4^{12}:4^{15})^{12}:4^{44}= [/tex]

[tex](4^{7+12-15})^{12}:4^{44}=4^{48}:4^{44}=4^4=256[/tex]
[tex][4^7*(-4)^{12}:(-4)^{15}]^{12}:4^{44}=[4^7*4^{12}*(-1)^{12}:4^{15}:(-1)^{15}]^{12}:4^{44} \\ =[4^4:(-1)]^{12}:4^{44}=(-4^{4})^{12}:4^{44}=4^{48}:4^{44}=4^4=256[/tex]