Răspuns:(m,n)=(3,11) sau (11,3)
a]2*2020=2*2020-2*2-2*2020+6= -4+6=2
b]x*y=xy-2x-2y+6=
(xy-2x)-2y+6=
x(y-2)-2y+4+2=
x(y-2)-2(y-2)+2=
(y-2)(x-2)+2=
(x-2)(y-2)+2
c) m *n=13=>
m*n=(m-2)(n-2)+2=13
(m-2)(n-2)=11=>
caz1
m-2=1
n-2=11=>
m=3
n=13
Caz2
m-2=11=> m=13
n-2=1 n=3
Explicație pas cu pas:
