Răspuns:
Explicație pas cu pas:
[tex](1,(3))^2+0,2 (6) * 1,5):2,8 \\\\((\frac{13-1}{9})^2 + \frac{26-2}{90} *\frac{15}{10}) : \frac{28}{10}\\\\((\frac{4}{3})^2 + \frac{4}{15} *\frac{3}{2}) : \frac{14}{5}\\\\(\frac{16}{9} + \frac{2}{5} ) * \frac{5}{14}\\\\\frac{16*5+18}{45} * \frac{5}{14}\\\\\frac{98}{45} * \frac{5}{14} = \boxed{\frac{7}{3} }\: \: sau \:\:\boxed{2,(3)}[/tex]
