Salut,
[tex](2\sqrt3)\colon\sqrt6=\dfrac{2\sqrt3}{\sqrt6}=\dfrac{2\sqrt3\sqrt6}{\sqrt6\sqrt6}=\dfrac{2\sqrt3\sqrt3\sqrt2}{6}=\dfrac{2\cdot 3\sqrt2}6=\sqrt2.[/tex]
Green eyes.
Răspuns:
Explicație pas cu pas:
(2√3):√6=2/√2=2√2/2=√2
