Date:
[tex]m_P=62g[/tex]
[tex]n_P=? [/tex]
[tex]N_P=? [/tex]
Formule:
[tex]n = \frac{m}{A} [/tex]
[tex]N=n \cdot N_A[/tex]
[tex]N_A=6,022 \cdot 10^{23} \frac{atomi}{mol} [/tex]
Rezolvare:
[tex]n_P=\frac {m_P} {A_P} = \frac{62 \not g}{31 \frac{\not g}{mol} } = 2 \: mol[/tex]
[tex]N_P=n_P \cdot N_A = 2 \:m ol\cdot6,022 \cdot10^{23} \frac{atomi}{mol} = 12,044 \cdot {10}^{23} atomi = 1,2044 \cdot {10}^{24} atomi[/tex] (am simplificat mol cu mol)
