Răspuns:
Explicație:
1.
Na I M= 23 + 127=150-----> 150g/moli ; 1mol Na I = 150g
Cu(NO3 )2 M= 64 + 2.14 + 6.16=188----> 188g/moli
1mol Cu(NO3)2 = 188g
K2CO3 M= 2.39 + 12 + 3.16=138----> 138g/moli
1mol K2CO3=138g
CaS M= 40 +32=72------> 72g/moli ; 1mol CaS= 72g
CaO M= 40 + 16=56------> 56g/moli ; 1mol CaO= 56 g
Na2SO4 M= 2.23 + 32 + 4.16=142-----> 142g/moli
1mol Na2SO4= 142g
Mg(OH)2 M= 24 + 2.16 +2=58--------> 58g/moli
1mol Mg(OH)2= 58g
2.
MCO2= 12+2.16=44-------> 44g/moli
n = m : M
n= 88g : 44g/moli=2 moli CO2
3.
MHNO3= 1+14 +3.16=63-------> 63g/moli
n= 6,3g : 63g/moli= 0,1 moli HNO3
4.
MCaSO4= 40 +32 + 4.16=136-------> 136g/moli
m= n . M
m= 0,5 moli. 136g/moli=68 g CaSO4
