[tex]\displaystyle\bf\\log_2\Big(log_3(x-1)\Big)=1\\\\\textbf{Argumentul primului logaritm este: }~~~~log_3(x-1)\\\\log_3(x-1)=2^1\\\\\textbf{unde 2 este baza primului logaritm, }\\\textbf{iar 1 este numarul ddin dreapta egalului.}\\\\log_3(x-1)=2\\\\x-1=3^2\\\\x-1=9\\\\x=9+1\\\\\boxed{\bf~x=10}[/tex]