Răspuns:
AD = mediana => BC = 2AD = 2×6cm = 12 cm
∠B = 60° => ∠C = 30° => (CnfT30°) => AB = BC/2 = 12cm/2 = 6 cm
Pitagora
AC = √BC² - AB² = √144 - 36 = √108 = √36×3 = 6√3 cm
AB = 6 cm ; BC = 12 cm ; AC = 6√3 cm
AB = AO => ΔBOC isoscel => ∠B = ∠C = 60° => ∠A = 180°-120° = 60° =>
ΔBOC = echilateral =>
=> BC = CO = BO = 12 cm
P(ΔBOC) = 12cm×3 = 36 cm