Răspuns:
c=mdx100/ms unde ms=md+m,apa
md= 80gNaOH
v,apa= 120ml
m,apa= 120mlx1 g/ml= 120g
ms= md+m,apa= 80+120=>200g
c= 80X100/200=>40%
c,m= niu/Vs
Vs= m,s/ro=200g/1,4726g/ml=135,8 ml=0,1358 l
niu=m/M=80g /40g/mol=2 mol
c,m= 2/0,1358 mol/l=14,7 mol/l
Explicație:
