Răspuns:
Explicație:
ms NaOH= 200g , c= 20%
r. cu HCl
a. masa de sare
b. nr. moli HCl
-se afla md sol. de NaOH
md= c .ms : 100
md= 20 . 200 : 100=40g NaOH
40g yg xg
NaOH + HCl= NaCl + H2O
40 g 36,5g 58,5g
x= 40 . 58,5 : 40=58,5 g NaCl
n= 58,5g : 58,5g/moli= 1mol NaCl
y= 40 . 36,5 : 40= 36,5 g HCl
n= 36,6g : 36,5 g/moli=1 mol HCl
-se afla ms HCl
ms= md . 100 : c
ms= 36,5 . 100 : 36,5=100 g sol. HCl
M HCl= 1+35,5=36,5 -----> 36,5g/moli
M NaOH= 23 +16 + 1=40-------> 40g/moli
