Răspuns:
ms=400g
C=40%
md=C×ms/100=400×40/100=160g
2×36,5g 111g 44g 18
CaCO3 + 2HCl => CaCl2 + CO2 + H2O
160g xgCaCl2 ygCO2 zgH2O
MHCl=AH+ACl=1+35,5=36,5g
MCaCl2 =ACa+2×ACl=40+2×35,5=111g
MCO2 =AC+2×AO=12+2×16=44g
MH2O=2×AH+AO=2×1+16=18g
x=160×111/2×36,5= calculează
y=160×44/2×36,5=calculează
z=160×18/2×36,5=calculează
n=m/M=160/36,5= 4,38 moli HCl
2moli 1mol 1mol 1mol
CaCO3 + 2HCl => CaCl2 + CO2 + H2O
4,38moli x'moli y'moli z'moli
x'=4,38×1/2=calculează
y'=4,38×1/2=calculează
z'=4,38×1/2=calculează
