Răspuns:
Deoarece bazele la aproape toate sunt aceleasi, se aduna sau se scad puterile(acolo unde este inmultire se aduna puterile si unde este impartire se scad puterile)
a. [tex](-\frac{2}{5} )^2 * (-\frac{2}{5} )^5 = (-\frac{2}{5} )^{(2+5)}=(-\frac{2}{5} )^7 = -\frac{125}{78125}[/tex]
b. [tex]1,5^4*1,5^3=1,5^{4+3}=1,5^7[/tex]
c. [tex][(-\frac{2}{3})^2]^3 = (-\frac{2}{3})^{2*3} =(-\frac{2}{3})^6=\frac{64}{729}[/tex]
d. [tex]\frac{3^{20}}{2^{30}}= \frac{3486784401}{1073741824}[/tex]
e. [tex]\frac{3}{4}* (\frac{3}{4})^4 : (\frac{3}{4})^3 = (\frac{3}{4})^1* (\frac{3}{4})^4 : (\frac{3}{4})^3 = (\frac{3}{4})^{1+4-3} = (\frac{3}{4})^2 = \frac{9}{16}[/tex]
f. [tex][(-\frac{1}{7})^{10}: (-\frac{1}{7})^8]*(-\frac{1}{7})^3 = (-\frac{1}{7})^{10-8+3}=(-\frac{1}{7})^{5}=-\frac{1}{16807}[/tex]
