Explicație pas cu pas:
1.
[tex]h = l \sqrt{3} \div 2[/tex]
[tex]h = 3 \sqrt{3} [/tex]
2.
[tex]h = l \sqrt{3} \div 2 \\ [/tex]
[tex]4 \sqrt{3} = l \sqrt{3 } \\ l = 4[/tex]
3. In orice triunghi dreptunghic cateta opusa unghiului de 30° = ip/2
Deci, c1=3 radical 2/2
Aplicam teorema lui Pitagora
[tex]ip ^{2} = c1^{2} + c2^{2} [/tex]
[tex]3 \sqrt{2} ^{2} = (3 \sqrt{2} \div 2) ^{2} + c2 ^{2} [/tex]
18=18/4+c2^2
C2^2=18-18/4
C2=radical 54/4
C2=(3 radical 6) /2
4. 2c^2=20^2
2C^2=400
C^2=200
C= radical 200
C= 10 radical 2
