Răspuns: 2CH4=C2H2+3H2 a=acetilena[etina] CH4=NH3+3/2O2=HCN+3H2O b =acid cianhidric C2H2+HCN=CH2=CH[CN} c=acrilonitril [cianoetena] nCH2=CH[CN]= {-CH2-CH[CN]}n rezulta prin polimerizare poliacrilonitril fibre sintetice tip melana b} compusii asi b se obtin din 3 moli de CH4 conform primelor 2 reactii Mpoliacrilonitril=MC3H3N=53g/mol la 3.22,4m3CH4.....................53kg acrilonitril x............................................212kg acrilonitril x=3.22,4.212/53=268,8m3 atentie amlificand reactiile cu n ,acesta se reduce
